Practice Questions: Voltage Drop
Real questions from our bank, all referenced to NEC 2026. Tap “Show explanation” after you answer.
What is the approximate voltage drop for a single-phase circuit with 40 amperes of load, 150 feet of copper conductors (K = 12.9 ohms·cmil/ft), using 6 AWG wire (26,240 cmil)?
- A3.7 volts
- B5.9 volts
- C7.4 volts
- D11.8 volts
Show explanation
VD = 2 × K × I × D / CM = 2 × 12.9 × 40 × 150 / 26,240 = 154,800 / 26,240 = 5.9V
For a 240-volt single-phase circuit, what is the maximum recommended voltage drop per NEC Informational Note for branch circuits and feeders combined?
- A2%
- B3%
- C5%
- D10%
Show explanation
NEC 210.19(A)(1) Informational Note recommends max 5% VD for branch circuits and feeders combined (3% branch, 2% feeder ideal).
A single-phase 120V circuit supplies a 20-amp load located 150 feet away. The circuit uses 12 AWG copper wire. Calculate the voltage drop.
- A2.89 volts (2.41%)
- B3.45 volts (2.88%)
- C4.12 volts (3.43%)
- D5.67 volts (4.73%)
Show explanation
Per NEC 210.19(A), use single-phase formula: VD = (2 × K × I × D) / CM. With copper K=12.9, 12 AWG has CM=6530. VD = (2 × 12.9 × 20 × 150) / 6530 = (77400) / 6530 = 3.45 volts. Percent VD = (3.45 / 120) × 100 = 2.88%. This is within the 3% branch circuit recommendation.
A 240V single-phase branch circuit serves a 30-amp water heater 200 feet away using 10 AWG aluminum conductor. What is the voltage drop?
- A4.87 volts (2.03%)
- B6.53 volts (2.72%)
- C8.19 volts (3.41%)
- D10.24 volts (4.27%)
Show explanation
For aluminum, K=21.2. Single-phase VD = (2 × K × I × D) / CM. 10 AWG = 10380 CM. VD = (2 × 21.2 × 30 × 200) / 10380 = (254400) / 10380 = 8.19 volts. Percent VD = (8.19 / 240) × 100 = 3.41%. This slightly exceeds the 3% recommendation, suggesting larger wire might be preferred.
A 120V single-phase feeder serves a 15-amp load at 100 feet using 14 AWG copper. Calculate the voltage drop.
- A1.49 volts (1.24%)
- B2.37 volts (1.98%)
- C3.56 volts (2.97%)
- D4.73 volts (3.94%)
Show explanation
Single-phase formula: VD = (2 × K × I × D) / CM. K=12.9 (copper), 14 AWG = 4110 CM. VD = (2 × 12.9 × 15 × 100) / 4110 = (38700) / 4110 = 1.49 volts. Percent VD = (1.49 / 120) × 100 = 1.24%. Well within acceptable limits.
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